2x^2+12=x^2+8x-4

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Solution for 2x^2+12=x^2+8x-4 equation: 



2x^2+12=x^2+8x-4

We move all terms to the left:

2x^2+12-(x^2+8x-4)=0

We get rid of parentheses

2x^2-x^2-8x+4+12=0

We add all the numbers together, and all the variables

x^2-8x+16=0

a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{2}=4$

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